local p = {}
local words = {"thousand", "million", "billion", "trillion"} -- We don't need to go higher than this, no-one knows what an octillion is.
-- For use by other scripts. Takes arguments:
-- - 1: string or number, value to convert
-- - forcenum: string for Template:Yesno, forces a result in digits for all n ≥ 10.
-- - formating options for spellnum: zero, adj, ord, us
-- WARNING: zero defaults to blank which is probably not what you want.
function p.spellnum(args)
local frame = mw.getCurrentFrame()
local numeral = tonumber(args[1])
-- Always return as digits for negative numbers, non-integers, and if (forcenum and numeral >= 10).
if numeral < 0 or
math.fmod(numeral, 1) ~= 0 or
(numeral >= 10 and frame:expandTemplate{ title = 'yesno', args = {args['forcenum']} } == 'yes') then
return mw.language.getContentLanguage():formatNum(numeral)
end
local spelled = frame:expandTemplate{ title = 'spellnum', args = {
numeral, zero = args['zero'], adj = args['adj'], ord = args['ord'], us = args['us']}}
if mw.ustring.find(spelled,'%a+[ %-]%a+[ %-]%a+') then
if numeral >= 1000000 and numeral <= 1000000000000000 then
local size = math.min(4, math.floor(math.log10(numeral) / 3))
numeral = numeral / 1000^size
return ({"%.2f ", "%.1f ", "%d "})[1 + math.floor(math.log10(numeral))]:format(numeral) .. words[size]
end
return mw.language.getContentLanguage():formatNum(numeral)
else
return spelled
end
end
function p.main(frame)
return p.spellnum(frame.args)
end
return p
